1. Anti-infection
  2. HCV
  3. Encofosbuvir

Encofosbuvir 是 HCV NS5B 聚合酶 (HCV NS5B polymerase) 的抑制剂,可抑制 GT1b、GT2a 和 GT3a,EC50 为 102.4,82.51 和 46.91 nM。Encofosbuvir 可抑制 HCV 复制,可用于哺乳动物丙型肝炎的研究。

MCE 的所有产品仅用作科学研究或药证申报,我们不为任何个人用途提供产品和服务

我们将采用定制合成服务的方式为您快速提供所需产品和技术服务

Encofosbuvir Chemical Structure

Encofosbuvir Chemical Structure

CAS No. : 2232134-77-7

1.  客户无需承担相应的运输费用。

2.  同一机构(单位)同一产品试用装仅限申领一次,同一机构(单位)一年内

     可免费申领三个不同产品的试用装。

3.  试用装只面向终端客户

规格 是否有货
50 mg   询价  
100 mg   询价  
250 mg   询价  

* Please select Quantity before adding items.

Customer Review

  • 生物活性

  • 纯度 & 产品资料

  • 参考文献

生物活性

Encofosbuvir is the inhibitor for HCV NS5B polymerase that inhibits GT1b, GT2a and GT3a with EC50 of 102.4, 82.51 and 46.91 nM. Encofosbuvir inhibits HCV replication and can be used for reseearchs of hepatitis C in mammals[1].

分子量

748.71

Formula

C30H42FN4O13PS

CAS 号
运输条件

Room temperature in continental US; may vary elsewhere.

储存方式

Please store the product under the recommended conditions in the Certificate of Analysis.

纯度 & 产品资料
参考文献

Encofosbuvir 相关分类

  • 摩尔计算器

  • 稀释计算器

The molarity calculator equation

Mass (g) = Concentration (mol/L) × Volume (L) × Molecular Weight (g/mol)

质量   浓度   体积   分子量 *
= × ×

The dilution calculator equation

Concentration (start) × Volume (start) = Concentration (final) × Volume (final)

This equation is commonly abbreviated as: C1V1 = C2V2

浓度 (start) × 体积 (start) = 浓度 (final) × 体积 (final)
× = ×
C1   V1   C2   V2
Help & FAQs
  • Do most proteins show cross-species activity?

    Species cross-reactivity must be investigated individually for each product. Many human cytokines will produce a nice response in mouse cell lines, and many mouse proteins will show activity on human cells. Other proteins may have a lower specific activity when used in the opposite species.

您最近查看的产品:

Your information is safe with us. * Required Fields.

   产品名称:

 

* 需求量:

* 客户姓名:

 

* Email:

* 电话:

 

* 公司或机构名称:

   留言给我们:

Bulk Inquiry

Inquiry Information

产品名称:
Encofosbuvir
目录号:
HY-172428
需求量: